1.

`(d^2x)/(dy^2)` equals: (1) `((d^2y)/(dx^2))^-1` (2) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^-3` (3) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^-2` (4) `-((d^2y)/(dx^2))^-1 ((dy)/(dx))^3`

Answer» `dy/dx = 1/(dx/dy)`
`(d^2 y)/dx^2 = d/dx (1/(dx/dy))dy/dx`
`= d/dy(1/(dx/dy))dy/dx`
`(d^2y)/(dx^2)= -1/(dx/dy)^2 (d^2x)/dy^2dy/dx`
`(d^2 x)/(dy^2) = -(d^2y)/(dx^2) (dx/dy)^2(dx/dy)`
`= - (d^2y)/dx^2 (dy/dx)^-3`
option 4 is correct


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