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D is the distance between the plates of a parallel plate capacitor. The dielectric constants are ∈1 and ∈2 respectively. The total capacitance is proportional to ____________(a) \(\frac{∈_1 ∈_2}{∈_1+∈_2}\)(b) ∈1 – ∈2(c) \(\frac{∈_1}{∈_2}\)(d) ∈1 ∈2This question was posed to me in unit test.This intriguing question comes from Advanced Problems on Network Theory topic in portion Network Theory and Complex Circuit Diagram of Network Theory |
Answer» RIGHT CHOICE is (a) \(\frac{∈_1 ∈_2}{∈_1+∈_2}\) Easiest explanation: The combination is equal to two capacitors in series. So, C = \(\frac{\BIG[∈_0 ∈_1 \LEFT(\frac{A}{0.5d}\right)\Big]\Big[∈_0 ∈_2 \left(\frac{A}{0.5d}\right)\Big]}{∈_0 ∈_1\frac{A}{0.5d} + ∈_0 ∈_1\frac{A}{0.5d}}\) Hence, C is proportional to \(\frac{∈_1 ∈_2}{∈_1+∈_2}\). |
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