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Three inductors each 30 mH are connected in delta. The value of inductance or each arm of equivalent star is _____________(a) 10 mH(b) 15 mH(c) 30 mH(d) 90 mHThe question was posed to me during an internship interview.The origin of the question is Advanced Problems Involving Complex Circuit Diagram topic in chapter Network Theory and Complex Circuit Diagram of Network Theory

Answer»

Correct option is (a) 10 mH

For EXPLANATION: We know that if an inductor L is connected in delta, then the equivalent star of each ARM = \(\FRAC{L X L}{L+L+L}\)

Given that, L = 30 mH

= \(\frac{30 X 30}{30+30+30}\)

= \(\frac{900}{90}\) = 10 mH.



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