1.

Dcotor has prescribed a lens having power+ 1.5D. What will be the focal length of the lens? What is the type of the lens and what must be the defect of vision?

Answer»

Solution :Given: Power = + 1.5 D
To find: Focal length
Type of lens
DEFECT of the eye
Solution : Power = `(1)/(f("in Meter"))`
+ 1.5 `= 1/f `
f` = 1/1.5`
`f = 1/1.5 XX 100 cm`
therefore f = + 66.67 cm`
`therefore f = + 0.67 m `
Type of lens = Convex lens
Defect in eye = hypermetropia or
FARSIGHTEDNESS.


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