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| 1. |
de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :A. `lambda = (12.3)/(sqrth) "Å"`B. `lambda = (12.3)/(sqrtV) "Å"`C. `lambda = (12.3)/(sqrtE) "Å"`D. `lambda = (12.3)/(sqrtm) "Å"` |
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Answer» Correct Answer - B |
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