1.

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:A. `"1.14 mol kg"^(-1)`B. `"3.28 mol kg"^(-1)`C. `"2.28 mol kg"^(-1)`D. `"0.44 mol kg"^(-1)`

Answer» Correct Answer - C
`m=(Mxx1000)/(1000d-Mm_(B))=(2.05xx1000)/(1000xx1.02-2.05xx60)`
`=2.28"mol kg"^(-1)`]


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