1.

Derive an expression for the heat produced by electric current and state Joule's Law.

Answer»

Solution :`P= Vxx(Q)/(T)`
P =VI
`H=Pxxt`
`= Vixxt = VIT`
H= IRIt [ V = IR , Ohm.s law ]
`=I^(2) Rt.`
Joule.s Law : When current of l ampere flows in a wire of RESISTANCE R `Omega` for t SECONDS, the heat energy disspated by it is given by `H= I^(2) Rt`


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