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Derive an expression for the variation of acceleration due to gravity below the surface of the Earth. |
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Answer» Solution :VARIATION of accleration due to gravity below the surface of earth : At a depth 'd' inside the ground mass of earth upto the point d from CETRE will exhibit force of attraction on the body. The remaining mass does not exhibit any influence. Mass of spherical body `M prop R^3` `:. M_s`/`M_E=(R_E-d)^3`/`R_E^3` where `M_S` is mass of earth's shell upto a depth 'd' from CENTRE. Gravitational force at depth 'd' is `F(d)=GM_s`m/`(R_E-d)^2=GM_Em(R_E-d)`/`R_E^2` `:.g(d)=(F(d))/(m)=(GM_E)/(R_E^3)(R_E-d)=g(R_E-d)=g(1-(d)/(R_E))` So 'g' VALUE decreases with depth below the ground. |
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