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InterviewSolution
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Determine a point which divides a line segment 6cm long externally in the ratio 5:3 |
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Answer» Solution :Steps of Construction 1. Draw a LINE segement AB=6cm. 2. Draw any ray making an acute `angleBAX` with AB. 3. ALONG AX, MARK off ( larger among the ratios ) 5 points `A_(1),A_(2),A_(3),A_(4),A_(5)` such that `A A_(1)=A_(1)A_(2)=A_(2)A_(3)=A_(3)A_(4)=A_(4)A_(5)`. 4. Join the point `A_(2)(5-3)` with end point B. 5. Draw a line parallel to `A_(2)B` from `A_(5)` ( larger among the ratios ) which MEETS AB produced at P. Point P, so obtained is the required point such that AP:BO=5:3. Justification: In`DELTAA A_(5)P`, Since `A_(2)B||A_(5)P` ( construction ) `:. (AP)/(BP)=(A A_(5))/(A_(2)A_(5))` ( By B.P. theorem ) `implies (AP)/(BP)=(5)/(3)` (construction ) 
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