Determine k so that (3k-2),(4k-6) and (k+2) are three consecutive term

1.	Determine k so that (3k-2),(4k-6) and (k+2) are three consecutive terms of an. Ap.
Answer» a1= (3k-2)a2= (4k-6)a3= (k+2)Now,a2-a1=a3-a2(4k-6)-(3k-2)=k+2-(4k-6)4k-6-3k+2=k+2-4k+6k-4=-3k+8K+3k=8+44k=12K=12/4K=3

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