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Determine the distance between the following pair of parallel lines: 4x + 3y – 11 = 0 and 8x + 6y = 15 |
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Answer» Given: The parallel lines are 4x + 3y – 11 = 0 and 8x + 6y = 15 To find: Distance between the givens parallel lines Explanation: The given parallel lines can be written as 4x + 3y − 11 = 0 … (1) 4x + 3y − \(\frac{15}{2}\) = 0 … (2) Let d be the distance between the given lines. ⇒ d =\(\Big|\frac{-11+\frac{15}{2}}{\sqrt{4^2+3^2}}\Big|\) = \(\frac{7}{2\times5}\) = \(\frac{7}{10}\) units Hence, distance between givens parallel line is \(\frac{7}{10}\) units |
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