1.

Determine the value of fuel burned during steady climb if SFC C is 0.000029 per second, thrust is 150KN and time required is 1500s.(a) 6.525 KN(b) 100N(c) 345(d) 87.87 NThe question was asked in my homework.This question is from Flight Mechanics in chapter Performance and Flight Mechanics of Aircraft Design

Answer»

Correct OPTION is (a) 6.525 KN

The best I can EXPLAIN: Fuel burned = SFC*Thrust*Time

= 0.000029*150*1500*1000 = 6.525KN.



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