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Determine the value of rudder deflection δr for an aircraft which is flying in north with the velocity of 60.5 m/s under the crosswind of 5m/s from east to west with Cnβ=0.02/deg and Cnδr = -0.045/deg, where sideslip angle β is -4.72°.(a) -2.09°(b) 3.5°(c) -4.5°(d) -4.74°The question was posed to me during an interview.This interesting question is from Lateral-Directional Static Stability and Control in division Stability, Control, and Handling Qualities of Aircraft Design

Answer» CORRECT CHOICE is (a) -2.09°

The explanation is: GIVEN, NORTH velocity n = 60.5m/s, East to west velocity e = 5m/s.

Now, rudder DEFLECTION δr = – [Cnβ/ Cnδr]*β = -[0.02/-0.045]*(-4.72) = -2.09°.


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