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Differentiate 3 sin^-1(e^2x) w.r.t x.(a) \(\frac{6e^2x}{\sqrt{1-e^{4x}}}\)(b) \(\frac{2e^2x}{\sqrt{1-e^{4x}}}\)(c) –\(\frac{6e^2x}{\sqrt{1-e^{4x}}}\)(d) \(\frac{6e^{-2x}}{\sqrt{1-e^{4x}}}\)This question was addressed to me by my school principal while I was bunking the class.This interesting question is from Exponential and Logarithmic Functions in section Continuity and Differentiability of Mathematics – Class 12 |
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Answer» The correct choice is (a) \(\frac{6E^2x}{\sqrt{1-E^{4X}}}\) |
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