1.

Differentiate 9^tan⁡3x with respect to x.(a) 9^tan⁡3x (3 log⁡9 sec^2⁡x)(b) 9^tan⁡3x (3 log⁡3 sec^2⁡⁡x)(c) 9^tan⁡3x (3 log⁡9 sec⁡x)(d) -9^tan⁡3x (3 log⁡9 sec^2⁡⁡x)The question was asked in semester exam.Origin of the question is Logarithmic Differentiation topic in portion Continuity and Differentiability of Mathematics – Class 12

Answer»

The correct OPTION is (a) 9^tan⁡3x (3 LOG⁡9 sec^2⁡x)

For explanation: CONSIDER y=9^tan⁡3x

Applying log on both sides, we get

log⁡y=log⁡9^tan⁡3x

Differentiating both sides with respect to x, we get

\(\frac{1}{y} \frac{dy}{dx}=\frac{d}{dx} \)(tan⁡3x.log⁡9)

\(\frac{1}{y} \frac{dy}{dx}=\frac{d}{dx} \,(tan⁡3x) \,log⁡9+\frac{d}{dx} \,(log⁡9).TAN3X \,(∵ Using \,u.v=u’ \,v+uv’)\)

\(\frac{dy}{dx}\)=y(3 sec^2⁡⁡x.log⁡9+0)

\(\frac{dy}{dx}\)=9^tan⁡3x (3 log⁡9 sec^2⁡x)



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