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Differentiate 4x^e^x with respect to x.(a) x^e^x e^-x (x logx+1)(b) -4x^e^x-1 e^x (x logx+1)(c) 4x^e^x e^x (x logx+1)(d) 4x^e^x-1 e^x (x logx+1)The question was posed to me during a job interview.Asked question is from Logarithmic Differentiation in portion Continuity and Differentiability of Mathematics – Class 12 |
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Answer» Right OPTION is (d) 4x^e^x-1 e^x (x logx+1) |
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