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Differentiate `sin3xcos5x` w.r.t .`x`. |
Answer» Let `y=sin 3x cos 5x=(1)/(2){2 cos 5x sin 3x}` `=(1)/(2){sin(5x+3x)-sin (5x-3x)}` `=(1)/(2).(sin 8x-sin 2x)=(1)/(2).(d)/(dx)(sin 2x)` `=((1)/(2).8 cos 8x-(1)/(2)xx2 cos2x)=(4 cos 8x -cos2x)`. |
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