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Differentiate the following function with respect of `x" ":1/(a x^2+b x^2+c)` |
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Answer» Let `y=1/(ax^(2)+bx+c) = (ax^(2)+bx+c)^(-1)` `therefore (dy)/(dx) = -(ax^(2)+bx+c)^(-2)(2ax + b)` [By chain rule] `=(-2ax+b)/(ax^(2)+bx+c)^(2)` |
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