Differentiate (x2 + 3x + 1) sin x

1.	Differentiate (x2 + 3x + 1) sin x
Answer» By Product Rule: (uv)′ = u′v + uv′ Here u = (x² + 3x + 1) and v = sin x [(x² + 3x + 1) sin x]’ = (2x + 3) × sinx + (x² + 3x + 1) × cosx = (2x + 3)sin x + (x² + 3x + 1)cos x

Answer»

By Product Rule: (uv)′ = u′v + uv′

Here u = (x² + 3x + 1) and v = sin x

[(x² + 3x + 1) sin x]’ = (2x + 3) × sinx + (x² + 3x + 1) × cosx

= (2x + 3)sin x + (x² + 3x + 1)cos x

Discussion

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