Differentiate x3 sec x

1.	Differentiate x3 sec x
Answer» By Product Rule: (uv)′ = u′v + uv′ Here u = x³ and v = sec x (x³ sec x)’ = 3x²(sec x) + x³(sec x tan x) = x²sec x(3 + x tan x)

Answer»

By Product Rule: (uv)′ = u′v + uv′

Here u = x³ and v = sec x

(x³ sec x)’ = 3x²(sec x) + x³(sec x tan x)

= x²sec x(3 + x tan x)

Discussion

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