1.

Distance between the lines 5x + 3y – 7 = 0 and 15x + 9y + 14 = 0 isA. \(\frac{35}{\sqrt{34}}\)  D. \(\frac{1}{3\sqrt{34}}\) C. \(\frac{35}{3\sqrt{34}}\) D. \(\frac{35}{2\sqrt{34}}\)

Answer»

The given lines can be written as 

5x + 3y − 7 = 0 … (1) 

5x + 3y + \(\frac{14}{3}\) = 0 ……(2) 

Let d be the distance between the lines 5x + 3y − 7 = 0 and 15x + 9y + 14 = 0 

Then, d = \(\Big|\frac{(-7-\frac{14}{2})}{\sqrt{5^2+3^2}}\Big|\) 

⇒ d = \(\frac{35}{3\sqrt{34}}\)



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