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Divide the sum of \(\frac{13}{5} \) and \(\frac{-12}{7}\) by the product of \(\frac{-31}{7}\) and \(\frac{1}{-2}.\) |
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Answer» Sum of \(\frac{13}{5}\) and \(\frac{-12}{7}\) \(\frac{13}{5}+\frac{-12}{7}\) \(=\frac{13\times7+(-12)\times5}{35}\) = \(\frac{91-60}{35}\) = \(\frac{31}{35}\) Product of \(\frac{-31}{7}\) and \(\frac{1}{-2}\) \(\frac{-31}{7}\times\frac{1}{-2}\) = \(\frac{-31\times1}{7\times-2}\) = \(\frac{-31}{-14}\) = \(\frac{31}{14}\) Now, According to the question, \(\frac{31}{35}\div\frac{31}{14}\) = \(\frac{31}{35}\times\frac{14}{31}\) = \(\frac{2}{5}\) |
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