1.

Divide the sum of \(\frac{13}{5} \) and \(\frac{-12}{7}\) by the product of \(\frac{-31}{7}\) and \(\frac{1}{-2}.\)

Answer»

Sum of \(\frac{13}{5}\) and \(\frac{-12}{7}\)

\(\frac{13}{5}+\frac{-12}{7}\)

\(=\frac{13\times7+(-12)\times5}{35}\)

\(\frac{91-60}{35}\)

\(\frac{31}{35}\)

Product of \(\frac{-31}{7}\) and \(\frac{1}{-2}\)

\(\frac{-31}{7}\times\frac{1}{-2}\)

\(\frac{-31\times1}{7\times-2}\)

\(\frac{-31}{-14}\)

\(\frac{31}{14}\)

Now,

According to the question,

\(\frac{31}{35}\div\frac{31}{14}\)

\(\frac{31}{35}\times\frac{14}{31}\)

\(\frac{2}{5}\)



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