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Divide the sum of \(\frac{-13}{5}\) and \(\frac{12}{7}\) by the product of \(\frac{-31}{7}\) and \(\frac{-1}{2}\) |
Answer» According to question, \(\frac{-13}{5}+\frac{12}{7}\) = \(\frac{-91+60}{35}\) = \(\frac{-30}{35}\) = \(\frac{-6}{7}\) And, \(\frac{-31}{7}\times \frac{1}{2}\) = \(\frac{-31}{14}\) Now, We have to divide \(\frac{-6}{7}\) by \(\frac{-31}{14}\) Therefore = \(\frac{-6}{7}\times \frac{14}{31}\) = \(\frac{-12}{31}\) |
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