1.

Divide the sum of \(\frac{-13}{5}\) and \(\frac{12}{7}\) by the product of \(\frac{-31}{7}\) and \(\frac{-1}{2}\)

Answer»

According to question,

\(\frac{-13}{5}+\frac{12}{7}\)

\(\frac{-91+60}{35}\)

\(\frac{-30}{35}\)

\(\frac{-6}{7}\)

And,

\(\frac{-31}{7}\times \frac{1}{2}\)

 = \(\frac{-31}{14}\)

Now,

We have to divide \(\frac{-6}{7}\) by \(\frac{-31}{14}\)

Therefore

\(\frac{-6}{7}\times \frac{14}{31}\)

\(\frac{-12}{31}\)



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