1.

Divide the sum of \(\frac{65}{12}\) and \(\frac{8}{3}\) by their differ-renice.

Answer»

According to the question,

\((\frac{65}{12}+\frac{8}{3})\div(\frac{65}{12}-\frac{8}{3})\)

\((\frac{65\times1+8\times4}{12})\div(\frac{65\times1-8\times4}{12})\)

\((\frac{65+32}{12})\div(\frac{65-32}{12})\)

\((\frac{97}{12})\div(\frac{33}{12})\)

\(\frac{97}{12}\times\frac{12}{33}\)

\(\frac{97}{33}\)



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