1.

Draw an angle of 110^(@) with the help of a protractor and bisect it. Measure each angle.

Answer»

SOLUTION :Draw `angleBXA = 110^(@)` with the help of a protractor. Now , we use the following STEPS for REQUIRED construction

(i) Taking `X` as centre and any radius daw an arc to intersect the rays `XA` and `XB`, say at `E` and `D`, respectively.
(ii) Taking `D` and `E` as centres and with the radius more than `(1)/(2)DE`, draw arcs to intersect each other say at `F`.
(iii) Draw the ray `XF`.
Thus , say `XF` is the required bisector of the angle `BXA`.
On measuring each angle , we GET `angleBXC = angleAXC = 55^(@)`
`[becauseangleBXC = angleAXC = (1)/(2)angleBXA = (1)/(2)xx110^(@) = 55^(@)]`


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