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Draw an angle of 60^(@). Draw its bisector. |
Answer» <P> Solution :Steps of construction :1. Draw a line segment `AB.` 2. Draw an angle of `60^(@)`. 3. With `P` as CENTRE and a convinient radius draw an arc. 4. With `Q` as centre and with the same radius draw ANOTHER arc cutting the previous arc at `D.` Join `AD.` Then `AD` is the required bisector of `angleBAC`. ![]() |
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