1.

Draw an angle of 60^(@). Draw its bisector.

Answer»

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Solution :Steps of construction :
1. Draw a line segment `AB.`
2. Draw an angle of `60^(@)`.
3. With `P` as CENTRE and a convinient radius draw an arc.
4. With `Q` as centre and with the same radius draw ANOTHER arc cutting the previous arc at `D.`
Join `AD.`
Then `AD` is the required bisector of `angleBAC`.


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