Draw the straight lines x-y+2=0 and 3x-8y=12 on the same graph pap[er (i) Find the point where the two lines meet each other. (ii) Find the area of traingle foprmed by these lines and x-axis.

Draw the straight lines x-y+2=0 and 3x-8y=12 on the same graph pap[er

1.	Draw the straight lines x-y+2=0 and 3x-8y=12 on the same graph pap[er (i) Find the point where the two lines meet each other. (ii) Find the area of traingle foprmed by these lines and x-axis.
Answer» Solution :We have x-y+2=0 x=y-2 When y =0 `rArr` x=-2 when y=1 `rArr` x=-1 When y =2 `rArr` x=0 when y=3 `rArr` x=1 Table for these values : Plot the points A(-2),B(-I,1), c(0,2),D(1,3) on the GRAPH paper and join them 3x-8y = 12 3x=8y+12 x=8y+12 3 When , y=0 `rArr` x=4 Wheny =-1.5 `rArr` x=0 Tables for these values plot the points p(4,0) and Q(0,-1.5) on the graph paper and joint them. (i) From the graph we see that the two lines intersect each other at R-(-5.6,-3.6). (ii) Area of triangle formed by these lines and x axis is `ar(triangle PAR) =(1)/(2)XX"base" xx "corresponding ALTITUDE"` `=(1)/(2)APxxMR=(1)/(2)xx(a+2)xx3.6 sq` units =10.8 sq units.