InterviewSolution
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दर्शाइये कि फलन `f(x)={{:((|x|)/(x)",",x ne 0),(1",",x = 0):} x = 0` पर असंतत है । |
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Answer» (i) `f(0) = 1` (ii) R.H.L. `=underset(x rarr 0^(+))(lim)f(x)=underset(h rarr 0)(lim)f(0+h)` `=underset(h rarr 0)(lim)(|0+h|)/((0+h))` `=underset(h rarr 0)(lim)(|h|)/(h)` `=underset(h rarr 0)(lim)(h)/(h)=1," "[because |x|=x]` (iii) L.H.L. `=underset(x rarr 0^(-))(lim)f(x)=underset(h rarr 0)(lim)f(0-h)` `=underset(h rarr 0)(lim)(|0-h|)/((0-h))` `=underset(h rarr 0)(lim)(|-h|)/(-h)` `=underset(h rarr 0)(lim)(h)/(-h)," "[because |-x|=x]` = -1. `therefore" "underset(x rarr 0^(+))(lim)f(x) ne underset(x rarr 0^(-))(lim)f(x)` अत: फलन f(x) बिन्दु x = 0 पर असंतत है । |
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