InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Drw a DeltaABC in which BC = 6 cm, CA = 5 cm and AB = 4 cm. Construct and triangle similar to it and of scale factor 3/5. |
|
Answer» SOLUTION :Here, SCALE factor is `5/3gt1,` so the resulting figure will be larger. Steps of Construction : 1. Draw BC = 6 cm. 2. Draw arc `BA_(1)=4` cm from B. 3. Draw arc `CA_(2)=5` cm from C. 4. Arc `CA_(2)and BA_(1)` intersect at A. 5. Join AB and AC. 6. Drew acute angle CBX below BC. 7. Cut BX into equal parts by arcs at `B_(1),B_(2),B_(3),B_(4)and B_(5).` 8. Join `B_(3)C.` 9. Draw `B_(5)C'"||"B_(3)C` by making ALTERNATE angles. C' is on BC produced. 10. Drew `C'A"||"CA` which meet BA produced at A'. Now, `DeltaA'BC` is the required triangle. Justification : `""DeltaBCB_(3)~DeltaBC'B_(5)""("by AA critertion of similarly")` `therefore""(BB_(3))/(BB_(5))-(BC)/(BC')""(BB_(1)=B_(1)B_(2)=...xthereforeBB_(3)=3xandBB_(5)=5X)` `implies""(3x)/(5x)=(BC)/(BC')` `""DeltaABC~DeltaA'BC'""("by AA criterion of similiarity")` `implies""(A'B)/(AB)=(A'C)/(AC)=(BC)/(BC')` 
|
|