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Dry air was passed successively through a solution of `5`g of a solute in `180`g water and then through pure water. The loss in weight of solutionwas `250`g and that of pure solvent `0.04`g . The molecular weight of the solute isA. `31.25`B. `3.125`C. `312.5`D. None of these |
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Answer» Correct Answer - A `P_(0)-P_(s)prop`loss in weight of water chamber and `P_(s)prop` loss in wt. of solution chamber. `(P^(@)-P_(S))/(P^(@))=(n)/(N)=(wxxM)/(mxxW)` or`(0.04)/(2.50)=(5xx18)/(mxx180)` `:. M=31.25` |
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