InterviewSolution
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InterviewSolution
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`(dy)/(dx)` ज्ञात कीजिए, जबकि- `y=(sinx+x^(2))/(cot2x)` |
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Answer» यहाँ `y=(sinx+x^(2))/(cot2x)` `rArry=(sinx+x^(2))tan2x` दोनों पक्षों का x के सापेक्ष अवकलन करने पर, `(dy)/(dx)=d/(dx)[(sinx+x^(2))tan2x]` `=(sinx+x^(2))d/(dx)(tan2x)+tan2xd/(dx)(sinx+x^(2))` `=(sinx+x^(2))(sec^(2)2x)d/(dx)(2x)+tan2x(d/(dx)sinx+d/(dx)x^(2))` `=2(sinx+x^(2))sec^(2)2x+tan2x(cosx+2x)` `=2(sinx+x^(2))sec^(2)2x+(cosx+2x)tan2x` |
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