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`(e^(x))/(logx)` का अवकल गुणांक x के सापेक्ष निकालें । |
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Answer» माना कि `y=(e^(x))/(logx)` अब , `(dy)/(dx)=(d)/(dx)((e^(x))/(logx))=(logx*(d)/(dx)(e^(x))-e^(x)*(d)/(dx)(logx))/((logx)^(2))` `=(logx*e^(x)-e^(x)*(1)/(x))/((logx)^(2))=(xe^(x)logx-e^(x))/(x(logx)^(2))=(e^(x)(xlogx-1))/(x(logx)^(2))` |
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