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Each hydrogen atom is excited by giving 10.2eV. The maximum number of spectral lines in the emission is equal toA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - A `E_(2) -E_(1) = 10.2ev`, so electron is excited to second orbit, therefore no of spectral lines `=(n(n-1))/(2)` |
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