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Each of the two guns,mounted on a rotating platform with their lengths parallel to each other, fires 20 bullets per second at a speed of 50 m s^(-1). If the perpendicular distance between the two guns is 1.2 m and the mass of each bullet is 25g, find the couple acting on the platform. |
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Answer» Solution :(i) FORCE = Impulse `div`Time (ii) Force on the GUN = force on the BULLETS = m `((v-U)/(t))`, where v and u are final and initial velocities of bullets, respectively, and m = mass of each bullet. (iii) Couple = force `xx` perpendicular distance between the forces. (iv) 30 N m |
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