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Eavaluate `lim_(x to 0) (sin^(2)2x)/(sin^(2)4x)` |
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Answer» Given, `underset(xto0)"lim"(sin^(2)2x)/(sin^(2)4x) = underset(xto0)"lim"(sin^(2)2x)/(sin2(2x))^(2)` `=underset(xto0)"lim"(sin^(2)2x)/(2sin2xcos2x)^(2)` `=underset(xto0)"lim"(1/(4cos^(2)2x))=1/4` `[therefore cos0=1]` |
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