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Electromagnetic radiation of wavelength `242` nm is just sufficient to ionise a sodium atom. Calculate the energy corresponding to this wavelength and the ionisation potential of Na. |
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Answer» Energy associated with a photon of 242nm =`(6.62xx10^(-34)xx3.0xx10^(8))/(242xx10^(-9)`=`8.21xx10^(-19)("joule")` `because` 1atom of Na for ionisation requires `=8.21xx10^(-19)J` `therefore6.023xx10^(23) ` atoms of Na for ionisation requires `=8.21xx10^(19)xx6.023xx10(23)` `=49.45xx10(4)J`=`494.5 KJ mol_(-1)` |
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