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Electromegnetic radiation of wavelength `500` nm is just safficient to ionic a sodium atom .Calculate the energy corresponding to this wavelength the ionisation potential of Na

Answer» Wavelength of radiation `= 300 xx 10^(-9)m`
Energy of radiation
`E = hv = (hc)/(lambda) `
`= (6.626 xx 10^(-34)Js xx 3 xx 10^(8) ms^(-1))/(300 xx 10^(-9)m)`
`= 6.626 xx 10^(-19) J`
Ionisation potential of Na
`N_(A) xx E ("where" N_(A) = "Avogadro number") = 6.023 xx 10^(23) xx 6.621 xx 10^(-19) J mol^(-1) = 398.7 kJ mol^(-1)`


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