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Electronmagnetic radiations having `lambda=310Å`are subjected to a metal sheet having work function `=12.8eV`. What will be the velocity of photoelectrons with maximum Kinetic Energy….A. 0, no emission will occurB. `4.352 xx 10^(6)m//s`C. `3.09 xx 10^(6)m//s`D. `8.72 xx 10^(6)m//s` |
Answer» Correct Answer - C `(hc)/(lambda) = phi +(1)/(2)mv^(2)` |
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