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Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength ` 6800` Å . Calculate threshold frequency `( v_0)` and work function `(W_0)` of the metal. |
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Answer» `E// "photon" = (hc)/(lambda) = ( 6.626 xx 10^(-34) xx 3.0 xx 10^8)/( 6800 xx 10^(-28)` . `= 2. 92 xx 10^(19) J` `E//" photon" = 2.92 xx 10^(-19) J` = work function (The ejection has zero velocity ) Threshold frequency `= c/(lambda) = ( 3 xx 10^8)/( 6800 xx 10^(-10))` ` = 4. 41 xx 10^(14) sec ^(-1)`. |
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