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Elevation in `b.p.` of an aqueous urea solution is `0.52^(@), (K_(b)=0.622^(@) "mol"^(-1)kg)` Hence, mole-fraction of urea in this solution is :A. `0.982`B. `0.567`C. `0.943`D. `0.018` |
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Answer» Correct Answer - D As `DeltaT_(b)="molality"xxK_(b)` `0.52=mxx0.52` molality`=1 "mol" kg^(-1)` `therefore` urea `=1` mol ` moles of water `=(1000)/(18)=55.55` mole fraction of urea `=(1)/(56.55)=0.018` |
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