InterviewSolution
Saved Bookmarks
| 1. |
Elevation of boiling point of 1 molar aqueous glucose solution `("density"=1.2g//ml)` isA. `"K"_("b")`B. 1.20 `"K"_("b")`C. 1.02`"K"_("b")`D. 0.98`"K"_("b")` |
|
Answer» Correct Answer - D Molality=1 `therefore "n"_("glucose")=1` `"W"_("glucose")=180"gm"` `"V"_("solution")=1000"mL"` `"W"_("solution")=1000xx1.2` =1200 gm `"W"_("solution")=1200-180=1020"gm"` `Delta"T"_("b")="K"_("b")xx("n"_("solute"xx1000))/("W"_("solvent"))=(1xx1000)/1020` `Delta"T"_("b")=0.98"K"_("b")` |
|