1.

Elevation of boiling point of 1 molar aqueous glucose solution `("density"=1.2g//ml)` isA. `"K"_("b")`B. 1.20 `"K"_("b")`C. 1.02`"K"_("b")`D. 0.98`"K"_("b")`

Answer» Correct Answer - D
Molality=1
`therefore "n"_("glucose")=1`
`"W"_("glucose")=180"gm"`
`"V"_("solution")=1000"mL"`
`"W"_("solution")=1000xx1.2`
=1200 gm
`"W"_("solution")=1200-180=1020"gm"`
`Delta"T"_("b")="K"_("b")xx("n"_("solute"xx1000))/("W"_("solvent"))=(1xx1000)/1020`
`Delta"T"_("b")=0.98"K"_("b")`


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