1.

Empirical formula of a compound is A_(2)B_(4). If its empirical formula weight is half of its vapour density, determine themolecular formula of the compound.

Answer»

`A_(4)B_(8)`
`A_(8)B_(16)`
`A_(2)B_(4)`
`A_(3)B_(6)`

Solution :Let the vapour density of COMPOUND be x Empirical formula weight = x/2
Molecular formula weight = 2X
`n=("Molecular formula weight")/("Empirical formula weight ")=(2x)/(x/2) = 4`
Molecular formula = `4 xx A_(2)B_(4) = A_(8)B_(16)`


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