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Energy of an electron in a particular orbit of single electron species of beryllium is the same as the energy of an electron in the ground state of hydrogen atom . Identify the orbit of berylliumA. 1B. 2C. 3D. 4 |
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Answer» Energy of an electron in `Be^(+3)` ion = `(-13.6)/(n^2)xx4^2ev` Energy of the electron in ground state hydrogen atom = -13.6 ev `therefore(-13.6)/(n^2)xx4^2=-13.6` `rArrn^2=42` `n=42` |
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