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Energy of electron of hydrogen atom in second Bohr orbit isA. `-5.44 xx 10^(-19) J`B. `-5.44 xx 10^(-19) kJ`C. `-5.44 xx 10^(-19) ` calD. `-5.44 xx 10^(-19) ` eV |
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Answer» Correct Answer - A `E=-(2.172xx10^(-18))/n^2=-(2.172xx10^(-18))/2^2` `=-5.44xx10^(-19)` J |
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