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Equal heat is given to two objects A and B of mass 1 g. Temperature of A increases by 3^@C and B by 5^@C. Which object has more specific heat? And by what factor?

Answer»


SOLUTION :HEAT absorbed by object `A(Q_A) =m_A c_A Delta T_A`
Heat absorbed by object `B(Q_B)= m_B c_B Delta T_B`
Given `Q_A = Q_B " and "m_A=m_B =1 g.`
Also, `DeltaT_A = 3^@C " and "Delta T_B= 5^QC`
`therefore c_A Delta T_A = c_B Delta T_B`
`therefore3c_A = 5c_B`
` thereforec_A = 5/3 c_B`


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