InterviewSolution
Saved Bookmarks
| 1. |
Equal volumes of ethylene glycol (molar mass = 62) and water (molar mass = 18) are mixed. The depression in freezing point of water is (given `K_(f)` of water `= 1.86 K mol^(-1)` kg and specific gravity of ethylene glycol is 1.11)A. `0.0033`B. `3.33C. `0.333`D. `33.3` |
|
Answer» `M=DxxV` M (Ethylene glycol) `= 1.11 xx upsilon` M (water) `= 1.00 xx upsilon` n(Ethylene glycol) = `(1.11 upsilon)/(62)` mol `Delta T_(f)= K_(f)xx m=1.86 xx (1.11 upsilon)/(62)xx(1000)/(1.00 upsilon)` `=(1.86xx1.11xx1000)/(62)=33.3` |
|