Equation of line passes through point (1, – 2) and perpendicular to – InterviewSolution

InterviewSolution

1.

Equation of line passes through point (1, – 2) and perpendicular to line 3x – 4y + 7 = 0 will be :(A) 4x + 3y – 2 = 0(B) 4x + 3y + 2 = 0(C) 4x – 3y + 2 = 0(D) 4x – 3y – 2 = 0

Answer»

Answer is (B) 4x + 3y + 2 = 0

Equation of line perpendicular to

3x – 4y + 7 = 0

4x + 3y + c = 0

It passes through point (1,2)

4(1) + 3(-2) + c = 0

⇒ 4 – 6 + c = 0

⇒ c – 2=0

⇒ c = 2

Thus, equation is 4x + 3y + 2 =0

Discussion

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