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Equimolar aqueous solutions of NaCI and `BACI_(2)` are prepared. If the freezing point of NaCI is `-2^(@)C`, the freezing point of `BaCI_(2)` solution is expected to be:A. `-2^(@)C`B. `-3^(@)C`C. `-1.5^(@)C`D. `-1.66^(@)C` |
Answer» Correct Answer - b `DeltaT_(f)("Colligative property")` in linked with number of particles or ions in solution `NaCItoNa_((aq))^(+)+CI_((aq))^(-)` ` BaCI_(2)toBa_((aq))^(2+)+2CI_((aq))^(-)` `"If "alph a"for " NaCI is -2^(@)C` `"Then " alpha "for" BaCI_(2) "is expected to be" =-3^(@)C.` |
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