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Evaluate:\(\int\cfrac{dx}{\sqrt{4x^2-1}}\)∫ dx/√(4x2-1) |
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Answer» Formula to be used - \(\int\cfrac{dx}{\sqrt{x^2\pm a^2}}=log(x+\sqrt{x^2\pm a^2})+c\), where c is the integrating constant \(\therefore\int\cfrac{dx}{\sqrt{4x^2-1}}\) \(= \int\cfrac{dx}{\sqrt{(2x)^{2}-1^2}}\) \(=\cfrac{1}{2}log|2x+\sqrt{4x^2-1}|+c\), c being the integrating constant |
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