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Evaluate: \(\int\frac{3x^2}{1 + x^3}dx\) |
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Answer» \(\int\frac{3x^2}{1 + x^3}dx\) = log(1 + x3)+c or using \(\int\frac{f'(x)}{f(x)}dx\) logf(x) + c put 1 + x3 = t ∴ 3x2dx = dt ∴ = ∫ \(\frac{1}{t}\)dt = log t + c = log(1 + x3) + c |
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