1.

Evaluate: \(\int\frac{3x^2}{1 + x^3}dx\)

Answer»

\(\int\frac{3x^2}{1 + x^3}dx\) = log(1 + x3)+c or using

\(\int\frac{f'(x)}{f(x)}dx\) logf(x) + c

put 1 + x3 = t

∴ 3x2dx = dt 

∴ = ∫ \(\frac{1}{t}\)dt = log t + c = log(1 + x3) + c



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